[질문] 외접원의중심구하는법좀..

세꼭지점이각각(x1,y1),(x2,y2),(x3, y3)이면외접원은세점을지나는원이므로 x²+y²+Ax+By+C=0이고,(x + A/2)² + (y + B/2)² = r² 형태가되므로(-A/2,-B/2)됩니다