ax^3+bx^2+cx+d=0(a≠0)의세개의근을α,β,γ라하면ax^3+bx^2+cx+d=a(x-α)(x-β)(x-γ)입니다.이것을우변을전개하여정리하면ax^3+bx^2+cx+d=ax^3-a(α+β+γ)x^
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