[질문] 1/sin(A) 의적분시 답은??

1/sin^2x=(1/sinx)^2=(cosex)^2=cose^2(x)적분공식1.∫sec^2(x)dx=tanx+C2.∫cose^2(x)dx=-cotx+C을적용하면,∫dx/sin^2x=-cotx+C입니다.