logaa=1loga1=0,logaX+logaY=loga(XY),logaX-logaY=loga(X/Y),logaB=logcB/logca(c는밑입니다..)----->c대신a를대입logaB/logaa=logaB(∵logaa=1)
[무물보AI] 답변 로딩중...