[질문] 약수개수구하는법

약수의개수공식을떠올려보면,x=a^p*b^q*...에서약수의개수=(p+1)*(q+1)...인데홀수라면p,q,,,가모두짝수입니다.따라서x=(a^p'*b^q'*..)^2으로다시쓸수있고요