[질문] 확률분포표준편차계산하는법

[(0.7^2*0.12^2)+(0.3^2*0.14^2)+2*1*0.7*0.3*0.12*0.14]=0.126=12.6%[(0.7^2*0.12^2)+(0.3^2*0.14^2)+2*0*0.7*0.3*0.12*0.14]=0.094=9.4%로 구하면 됩니다~