①(x+2)(x-3)+6x=x^2-x-6+6x=(x+6)(x-1).//②(x+y)^2+(x+y)(x-y)를(x+y)로묶으면(x+y)(x+y+x-y)=(x+y)2x.//③(x-y-2)(x-y+3)에서(x-y)=T로놓으면T^2+T-6
[무물보AI] 답변 로딩중...